Найдите массу 19,6% этого раствора серной кислоты,способного ...

Дмитрий

СH3-NH2+H2SO4= CH3-NH3HSO4

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n(CH3-NH2)=11,2/22,4=0,5моль;

n(H2SO4)=0,5; m(H2SO4)в растворе =0,5*98=49г;

m(H2SO4)раствора =49/0,196=250г;

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